标题：图片压缩上传后 的js 问题 如何传递当前表的id

function submitForm(strkey){


				show("tst1",2000);
    var result = submitAjaxForm('form1','afterSubmit');
}

function afterSubmit(result){

				hide("tst1");
    if (result=='OK') {

				show("tst2");

				location="BanzuKaoqinMingxieditdetail?did="  ？？？;

				}

				else{

				show("tst3",2000);

				}
}

						With
						wb.AddButtonGroup("form1","btg1",True)
   .Add("btn1", "确定", "button").Attribute= ""
					'调用js函数上传
        End
						With

如何把当前表的 strkey 传递到 ？？？里面