[求助]逻辑列在目录树节点显示 - 专家坐堂 - Foxtable(狐表) - 新一代数据库软件，完美融合Access、Foxpro、Excel、vb.net之优势，人人都能掌握的快速软件开发工具!

老师，在目录树显示逻辑列时，如何让 false 显示为未付款 true 显示为已付款？谢谢！

此主题相关图片如下：qq图片20180520105253.png

循环修改

Dim trv As WinForm.TreeView = e.Form.Controls("TreeView1")
For Each nd As WinForm.TreeNode In trv.AllNodes
    If nd.level = 1 Then
        If nd.Text = "False" Then
            nd.text = "否"
        Else
            nd.text = "是"
        End If
    End If
Next

老师，在下面代码中报错。在单选未付款或已付款时就报错，如果勾选供货单位没得问题。

.NET Framework 版本：2.0.50727.8762

Foxtable 版本：2018.3.9.1

错误所在事件：

详细错误信息：

无法在 System.Boolean 和 System.String 上执行“=”操作。

Dim Lbs As String() ={"供货单位","确认付款","金额","日期"} '目錄樹級數

Dim trv As WinForm.TreeView = e.Sender

Dim nd,nd1 As WinForm.TreeNode

Dim flt,s1 As String

Dim n1,Inum As Integer

nd = trv.SelectedNode

For Each nd1 In nd.allNodes '同步子节点选中状态

nd1.Checked = nd.Checked

If nd.ParentNode IsNot Nothing Then '确定父节点选中状态:

For n1 = nd.ParentNode.level To 0 Step -1 '

Inum = nd.ParentNode.Nodes.Count '利用muhua老师的

For Each nd1 In nd.ParentNode.Nodes

Inum+ = Val(nd1.Checked)

nd.ParentNode.Checked = (Inum = 0)

nd = nd.ParentNode

End If

For Each nd In trv.AllNodes

If nd.Level > 0 AndAlso nd.ParentNode.Checked Then '如果父节点选中

Continue For '跳过此节点,处理下一结点

End If

If nd.Checked Then

n1=0

For Each s1 In nd.FullPath.split("\")

flt+ =iif(n1 =0,") Or (" ," and ") & Lbs(n1) & " = '" & s1 & "'"

n1+=1

End If

If flt IsNot Nothing Then

e.Form.Controls("TextBox1").value = flt.Substring(4) & ")"

Tables("疫苗药品入库单").Filter = flt.Substring(4) & ")"

End If

参考这里的做法

http://www.foxtable.com/webhelp/scr/2503.htm

Dim nms As String() = {"产品","客户","雇员"} '指定生成目录树的各列
Dim qts As String() = {"'","'","'"} '指定将各列的值括起来的符号,这里都是字符型,所以都是单引号
Dim trv As WinForm.TreeView = e.Sender
Dim flt As String
Dim nd As WinForm.TreeNode
For Each nd In e.node.allNodes '清除子节点的选中标记
    nd.Checked = False
Next
nd = e.Node.ParentNode
Do While nd IsNot Nothing '清除父节点的选中标记
    nd.Checked = False
    nd = nd.ParentNode
Loop
For Each nd In trv.AllNodes
    If nd.Checked Then
        Dim rts() As String = nd.FullName.Split("\")
        Dim val As String = ""
        For i As Integer = 0 To rts.length - 1
            If val > "" Then
                val = val & " And "
            End If
            val = val & nms(i) & " = " & qts(i) & rts(i) & qts(i)
        Next
        If flt > "" Then
            flt = flt & " Or (" & val & ")"
        Else
            flt = val
        End If
    End If
Next
Tables("订单").Filter = flt

或者你试试把

For Each s1 In nd.FullPath.split("\")

改成

For Each s1 In nd.FullName.split("\")

主题：[求助]逻辑列在目录树节点显示