主题：考勤相同小时排除

如何将一个人在同一天里相同的小时内的多余考勤数据排除？举例：比如早上上班时间：同一个人打了两次卡，就形成两条记录，如何将多余的记录删除？

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点击浏览该文件:管理项目2.foxdb

参考代码

 

Dim idx As String = "-1,"
Dim idx_temp As String = ""
Dim pdr As DataRow = Nothing
Dim count As Integer = 0
Dim cs As String = "第一列,第二列"
For Each dr As DataRow In DataTables("表A").Select("", cs)
    Dim flag As Boolean = False
    If pdr IsNot Nothing Then
        If pdr("第一列") <> dr("第一列") OrElse format(pdr("第二列"),"yyyyMMddHH") <> format(dr("第二列"), "yyyyMMddHH")  Then
            flag = True
        End If
    End If
    If flag Then
        If count > 1 Then
            idx &= idx_temp
        End If
        count = 1
        idx_temp = ""
    Else
        count += 1
        idx_temp &= dr("_Identify") & ","
    End If
   
    pdr = dr
Next

If count > 1 Then
    idx &= idx_temp
End If

'Tables("表A").filter = "_Identify in (" & idx.trim(",") & ")"
Tables("表A").filter = "_Identify not in (" & idx.trim(",") & ")"

谢谢！如果间隔时间为5分钟以上就算是有效打卡？这个代码应该怎么改？

Dim idx As String = "-1,"
Dim idx_temp As String = ""
Dim pdr As DataRow = Nothing
Dim count As Integer = 0
Dim cs As String = "第一列,第二列"
For Each dr As DataRow In DataTables("表A").Select("", cs)
    Dim flag As Boolean = False
    If pdr IsNot Nothing Then
        Dim sp As TimeSpan = dr("第二列") - pdr("第二列")
        If pdr("第一列") <> dr("第一列") OrElse sp.TotalMinutes >= 5  Then
            flag = True
        End If
    End If
    If flag Then
        If count > 1 Then
            idx &= idx_temp
        End If
        count = 1
        idx_temp = ""
    Else
        count += 1
        idx_temp &= dr("_Identify") & ","
    End If
   
    pdr = dr
Next

If count > 1 Then
    idx &= idx_temp
End If

Tables("表A").filter = "_Identify in (" & idx.trim(",") & ")"
'Tables("表A").filter = "_Identify not in (" & idx.trim(",") & ")"

谢谢!居然忘记用时段来做判断!