主题：根据文件名打开文件

呃，不明白你什么意思

Dim Proc As New Process
Proc.File = ProjectPath & "中兴规格书\" & e.Row("物料代码") & " RV 1.5.xls"
Proc.Start()

要不，你就循环所有文件，看是否匹配，匹配就打开

Dim files() As String  = System.IO.Directory.GetFiles("d:\", "test*.xls")

For Each file As String In files
    msgbox(file)
Next

Dim files() As String  = System.IO.Directory.GetFiles(ProjectPath & "中兴规格书\" ,  e.Row("代码") & "*.xls")

For Each file As String In files
    Dim Proc As New Process
    Proc.File = file
    Proc.Start()
Next