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主题:索引代码问题

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  发帖心情 Post By:2011/11/29 8:54:00 [显示全部帖子]

贴出代码

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  发帖心情 Post By:2011/11/29 16:19:00 [显示全部帖子]

看不出问题来,做个简单例子,保留两行数据,说名怎样输入数据,会出现你所说的错误提示。

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  发帖心情 Post By:2011/11/29 16:39:00 [显示全部帖子]

呵呵,千言万语,不如一个实例。

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  发帖心情 Post By:2011/11/30 9:53:00 [显示全部帖子]

如果在原料指标_SiO2硅_实测输入值,但是你的理化厂表中原料指标_SiO2硅是空值,而你的代码又没有判断,不出错才奇怪。

加上判断即可: 

 

Select Case e.DataCol.name
    Case "原料指标_MgO镁_实测","原料指标_SiO2硅_实测","原料指标_CaO钙_实测","原料指标_Fe2O3铁_实测","原料指标_Al2O3铝_实测","原料指标_CaO比SiO2_实测","原料指标_Cr2O3铬_实测","原料指标_FeO加Fe2O3_实测","原料指标_Na2O氧化钠_实测","原料指标_BD体密_实测","原料指标_AP气孔_实测","原料指标_CR比FE_厂标","成品指标_MgO镁_实测","成品指标_Cr2O3铬_实测","成品指标_Fe2O3铁_实测","成品指标_Al2O3铝_实测","成品指标_CaO钙_实测","成品指标_SiO2硅_实测","成品指标_BD体密_实测","成品指标_AP气孔_实测","成品指标_LOI烧碱_实测","成品指标_CCS耐压_实测","成品指标_抗折_常温_实测","成品指标_抗折_高温_实测","成品指标_热震_水泠_实测","成品指标_热震_风泠_实测","成品指标_RUL菏软_实测"
        Dim dr As DataRow = DataTables("理化厂标").Find("牌号 = '" & e.DataRow("牌号") & "'")
        If dr IsNot Nothing AndAlso e.newvalue Then
            Dim nm As String = e.DataCol.Name.SubString(0,e.DataCol.Name.LastIndexof("_"))
            If dr.IsNull(nm) =False Then
                Dim ov As String = dr(nm)
                If Isnumeric(ov) Then
                    Dim v As Double = ov
                    If e.NewValue = v Then
                        e.DataRow(nm & "_" & "厂标" ) = "合格"
                    ElseIf  e.NewValue > v Then
                        e.DataRow(nm & "_" & "厂标" ) = e.newvalue -v
                    Else
                        e.DataRow(nm & "_" & "厂标" ) = v - e.newvalue
                    End If
                ElseIf  ov.IndexOf("-") > 0 Then
                    Dim vls() As String = ov.split("-")
                    Dim v1 As Double = vls(0)
                    Dim v2 As Double = vls(1)
                    If e.newvalue >= v1 AndAlso e.newvalue <= v2 Then
                        e.DataRow(nm & "_" & "厂标" ) = "合格"
                    ElseIf e.newvalue < v1 Then
                        e.DataRow(nm & "_" & "厂标" ) = e.newvalue - v1
                    Else
                        e.DataRow(nm & "_" & "厂标" ) = e.newvalue - v2
                    End If
                Else
                    Dim o As String = ov.SubString(0,1)
                    Dim v As Double = val(ov.SubString(1))
                    If o = ">" Then
                        If e.NewValue > v Then
                            e.DataRow(nm & "_" & "厂标" ) = "合格"
                        Else
                            e.DataRow(nm & "_" & "厂标" ) = v - e.newvalue
                        End If
                    ElseIf o = "<"
                        If e.NewValue < v Then
                            e.DataRow(nm & "_" & "厂标" ) = "合格"
                        Else
                            e.DataRow(nm & "_" & "厂标" ) =  e.newvalue - v
                        End If
                    ElseIf o = "≥" Then
                        If e.NewValue >= v Then
                            e.DataRow(nm & "_" & "厂标" ) = "合格"
                        Else
                            e.DataRow(nm & "_" & "厂标" ) = v - e.newvalue
                        End If
                    ElseIf o = "≤"
                        If e.NewValue <= v Then
                            e.DataRow(nm & "_" & "厂标" ) = "合格"
                        Else
                            e.DataRow(nm & "_" & "厂标" ) =  e.newvalue - v
                        End If
                    End If
                End If
            End If
        End If
End Select

 

建议看看:

http://www.foxtable.com/help/topics/1485.htm

 

 

 

 

 

[此贴子已经被作者于2011-11-30 9:54:11编辑过]

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  发帖心情 Post By:2011/12/2 8:16:00 [显示全部帖子]

单精度如何输入 _ >=这些符号?

 

 


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