<%
url = "http://service2.winic.org/Service.asmx" 'webservice 地址
'==============================查询账户信息
function GetUserInfo(uid,pwd)
SoapRequest="<?xml version="&CHR(34)&"1.0"&CHR(34)&" encoding="&CHR(34)&"utf-8"&CHR(34)&"?>"& _
"<soap:Envelope xmlns:xsi="&CHR(34)&"http://www.w3.org/2001/XMLSchema-instance"&CHR(34)&" "& _
"xmlns:xsd="&CHR(34)&"http://www.w3.org/2001/XMLSchema"&CHR(34)&" "& _
"xmlns:soap="&CHR(34)&"http://schemas.xmlsoap.org/soap/envelope/"&CHR(34)&">"& _
"<soap:Body>"& _
"<GetUserInfo xmlns="&CHR(34)&"http://tempuri.org/"&CHR(34)&">"& _
"<uid>"&uid&"</uid>"& _
"<pwd>"&pwd&"</pwd>"& _
"</GetUserInfo>"& _
"</soap:Body>"& _
"</soap:Envelope>"
Set xmlhttp = server.CreateObject("Msxml2.XMLHTTP")
xmlhttp.Open "POST",url,false
xmlhttp.setRequestHeader "Content-Type", "text/xml;charset=utf-8"
xmlhttp.setRequestHeader "HOST","service2.winic.org"
xmlhttp.setRequestHeader "Content-Length",LEN(SoapRequest)
xmlhttp.setRequestHeader "SOAPAction", "http://tempuri.org/GetUserInfo" '一定要与WEBSERVICE的命名空间相同，否则服务会拒绝
xmlhttp.Send(SoapRequest)
''样就利用XMLHTTP成功发送了与SOAP示例所符的SOAP请求.'检测一下是否返回200=成功：
If xmlhttp.Status = 200 Then
Set xmlDOC = server.CreateObject("MSXML.DOMDocument")
xmlDOC.load(xmlhttp.responseXML)
GetUserInfo=xmlDOC.documentElement.selectNodes("//GetUserInfoResult")(0).text '显示节点为GetUserInfoResult的数据(返回字符串)
Set xmlDOC = nothing
Else
GetUserInfo=xmlhttp.Status&" "
GetUserInfo=xmlhttp.StatusText
End if
Set xmlhttp = Nothing
end function
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Post By：2016/1/9 14:24:00 [只看该作者]
