老师您好，我想问一下web端删除怎么跟foxtable进行一个同步，我的web代码是<script type="text/html" id='barDemo'>
<a class="layui-btn layui-btn-xs" lay-event="detail">查看</a>
<a class="layui-btn layui-btn-xs" lay-event="edit">编辑</a>
<a class="layui-btn layui-btn-xs layui-btn-danger" lay-event="del">删除</a>
</script>
tb.on('tool',function(obj){
if(obj.event=='editDate'){
layui.laydate.render({
elem:$(this).children()[0],
show:true,
closeStop:this,
done:function(value,date){
var field=$(this).data('field');
obj.data[field]=value;
}
});
}else if (obj.event=='detail'){
layer.msg('['+obj.data.单号+']的查看操作');
}else if (obj.event=='del'){
layer.confirm('真的要删除吗',function(index){
obj.del();
Layer.close(index);
});
}else if (obj.event=='edit'){
layer.alert('编辑行:<br>'+JSON.stringify(obj.data))
}
});
加好友 
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Post By：2021/11/9 14:03:00 [只看该作者]
