寻求子节点定位方法

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点击浏览该文件:管理项目17.rar

麻烦的解决方法。

Dim cmd As New SQLCommand
cmd.CommandText = "Select {表A}.[第一列] As [分组],{表B}.[第一列] As [样式] from {表A} inner join {表B} on {表A}.[样式]={表B}.[_Identify]"
Dim dt As datatable
dt = cmd.ExecuteReader()

Dim tr As WinForm.TreeView = e.Form.Controls("TreeView1")
Dim tn As WinForm.TreeNode
tr.ExpandAll
Dim ys() As String = dt.GetComboListString("样式").Split("|")   \'获取图标样式的总类数
For Each y As String In ys
    For Each ysr As DataRow In dt.Select("样式 = \'" & y & "\'")   \'遍历列表样式=当前样式
        Dim xxx() As String = ysr("分组").Split("\\")
        output.show(xxx.Length)
        Select Case xxx.Length
            Case 1
                tr.nodes(xxx(0)).IconFile = y & ".ico"
            Case 2
                tr.nodes(xxx(0)).nodes(xxx(1)).IconFile = y & ".ico"
            Case 3
                tr.nodes(xxx(0)).nodes(xxx(1)).nodes(xxx(2)).IconFile = y & ".ico"
            Case 4
            Case 5
            Case 6
            Case 7
            Case 8
            Case Else
               
        End Select
    Next
Next

已经不错了