以文本方式查看主题 - Foxtable(狐表) (http://foxtable.com/bbs/index.asp) -- 专家坐堂 (http://foxtable.com/bbs/list.asp?boardid=2) ---- 列出科目详细名称 (http://foxtable.com/bbs/dispbbs.asp?boardid=2&id=158740) |
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-- 作者:zhuxinhui -- 发布时间:2020/12/1 11:32:00 -- 列出科目详细名称
Dim dr1 As DataRow = e.DataRow Dim str1 As String Dim st As String Select Case e.DataCol.Name Case e.DataRow("科目编码").length >= 4 Dim strr As String = e.DataRow("科目编码").substring(0,4) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") st = fdr("科目名称") \' MessageBox.Show("4") Case e.DataRow("科目编码").length >= 8 Dim strr As String = e.DataRow("科目编码").substring(0,8) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") \'Dim fdr As DataRow = DataTables("科目表").find("& strr &=\'" & dr1("科目编码") & "\'") st = fdr("科目名称") str1 &= "-"& st Case e.DataRow("科目编码").length >= 12 Dim strr As String = e.DataRow("科目编码").substring(0,12) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") \'Dim fdr As DataRow = DataTables("科目表").find("& strr &=\'" & dr1("科目编码") & "\'") st = fdr("科目名称") str1 &= "-"& st Case e.DataRow("科目编码").length >= 16 Dim strr As String = e.DataRow("科目编码").substring(0,16) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") \'Dim fdr As DataRow = DataTables("科目表").find("& strr &=\'" & dr1("科目编码") & "\'") st = fdr("科目名称") str1 &= "-"& st Case e.DataRow("科目编码").length >= 18 Dim strr As String= e.DataRow("科目编码").substring(0,18) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") \'Dim fdr As DataRow = DataTables("科目表").find("& strr &=\'" & dr1("科目编码") & "\'") st = fdr("科目名称") str1 &= "-"& st Case Else e.DataRow("科目详细名称")= str1 End Select 老是提示字符串转换出问题
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-- 作者:有点蓝 -- 发布时间:2020/12/1 11:41:00 -- Dim dr1 As DataRow = e.DataRow Dim str1 As String Dim st As String Select Case e.DataCol.Name case "科目编码","科目名称" if e.DataRow("科目编码").length >= 4 Dim strr As String = e.DataRow("科目编码").substring(0,4) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") if fdr isnot nothing then st = fdr("科目名称") end if \' MessageBox.Show("4") elseif e.DataRow("科目编码").length >= 8 Dim strr As String = e.DataRow("科目编码").substring(0,8) Dim fdr As DataRow = DataTables("科目表").find("科目编码=\'" & strr & "\'") if fdr isnot nothing then st = fdr("科目名称") str1 &= "-"& st end if else.............
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-- 作者:有点蓝 -- 发布时间:2020/12/1 12:08:00 -- Select Case e.DataCol.Name Case "科目编码","科目名称" If e.DataRow.IsNull("科目编码") = False Dim st As String = e.DataRow("科目编码") Dim str1 As String = e.DataRow("科目名称") Do While st.Length > 4 st = st.substring(0,st.Length - 4) Dim fdr As DataRow = e.DataTable.find("科目编码=\'" & st & "\'") If fdr IsNot Nothing Then str1 = fdr("科目名称") & "-" & str1 End If Loop e.DataRow("科目详细名称")= str1 End If End Select
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