以文本方式查看主题 - Foxtable(狐表) (http://foxtable.com/bbs/index.asp) -- 专家坐堂 (http://foxtable.com/bbs/list.asp?boardid=2) ---- 如何遍历日志表,生成josn文件内容呢? (http://foxtable.com/bbs/dispbbs.asp?boardid=2&id=152744) |
-- 作者:李孝春 -- 发布时间:2020/7/20 16:07:00 -- 如何遍历日志表,生成josn文件内容呢? 现有一表“日志”有如下字段和内容 Dim jo As New JObject Dim ja As New JArray jo("danweiname") = "AAA" jo("name") = "BB" jo("date") = ja \' ja.Add(New JObject) \'给数组添加两个对象成员 ja.Add(New JObject) ja(0)("time") = "2020-12-11" ja(0)("context") = "下午" ja(1)("time") = "2020-12-12" ja(1)("context") = "中午" Output.Show(jo.ToString) 上述代码可以固定生成 { "danweiname": "AAA", "name": "BB", "date": [ { "time": "2020-12-11", "context": "下午" }, { "time": "2020-12-12", "context": "中午" } ] } 随着日志表记录越来越多 这个相对固定生成josn的形式就不大方便了 有没有办法实现如下功能呢? 1、根据日志表中的danweiname name time三个字段作为条件 分类生成context内容 2、先判断danweiname 如上josn结果 先显示单位名称 (若遇多个单位:需要先一个单位显示完毕了才生成下一个单位的) 3、判断name,如上josn结果 根据单位名称 显示name (若遇一个单位,日志记录里有多个name值相同的,先显示完毕了才显示下一个name的相关内容) 4、判断time且满足danweiname name的条件时,如上josn结果 根据time先后顺序进行数据生成 并显示context的对应值 |
-- 作者:有点蓝 -- 发布时间:2020/7/20 16:29:00 -- 使用getvalues+select遍历即可 \'定义数组集合的时候,要在类型后加上括号,表示这是一个数组集合。 Dim Arys As List(Of String()) Arys = DataTables("订单").GetValues("danweiname|name") \'列名用符号|分割 \'注意循环变量是字符型数组,所以类型是String(),而不是String For Each Ary As String() In Arys Output.Show(Ary(0) & "|" & Ary(1)) for each dr as datarow in DataTables("订单").select("danweiname= \'" & Ary(0) & "\' and name=xxxx") Output.Show(dr(“time”)) next Next
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-- 作者:李孝春 -- 发布时间:2020/7/20 17:05:00 -- 回复:(有点蓝)使用getvalues+select遍历即可'定义数... Dim Arys As List(Of String()) Arys = DataTables("josn").GetValues("danweiname|name") \'列名用符号|分割 \'注意循环变量是字符型数组,所以类型是String(),而不是String For Each Ary As String() In Arys Output.Show(Ary(0) & "|" & Ary(1)) Dim jo As New JObject Dim ja As New JArray jo("danweiname") = Ary(0) jo("name") = Ary(1) jo("date") = ja \' ja.Add(New JObject) \'给数组添加两个对象成员 ja.Add(New JObject) For Each dr As DataRow In DataTables("josn").Select("danweiname= \'" & Ary(0) & "\' and name=\'" & Ary(1) & "\'") Output.Show(dr("tiem")) Output.Show(dr("context")) ja(0)("tiem") = dr("tiem") ja(0)("context") = dr("context") ja(1)("tiem") = dr("tiem") ja(1)("context") = dr("context") Output.Show(jo.ToString) Next Next 红色部分启用之后 会报错 不启用 则生成如下: 2012-12-12 下午 { "danweiname": "AAA", "name": "BB" } 2020-11-11 中午 { "danweiname": "AAA", "name": "BB" } 2020-11-11 WANSHANG { "danweiname": "AAA", "name": "BB" } 2012-11-12 CE { "danweiname": "AAA", "name": "CC" } 2012-11-13 ZHONGWU { "danweiname": "BBB", "name": "QQ" } |
-- 作者:有点蓝 -- 发布时间:2020/7/20 17:13:00 -- Dim Arys As List(Of String()) Arys = DataTables("josn").GetValues("danweiname|name") \'列名用符号|分割 \'注意循环变量是字符型数组,所以类型是String(),而不是String Dim jaaa As New JArray Dim jo,jo2 As JObject For Each Ary As String() In Arys Output.Show(Ary(0) & "|" & Ary(1)) jo = New JObject jo("danweiname") = Ary(0) jo("name") = Ary(1) jo("date") = New JArray\' For Each dr As DataRow In DataTables("josn").Select("danweiname= \'" & Ary(0) & "\' and name=\'" & Ary(1) & "\'") Output.Show(dr("tiem")) Output.Show(dr("context")) jo2 = New JObject jo2("tiem") = dr("tiem") jo2("context") = dr("context") jo("date").add(jo2) Next jaaa.Add(jo) Next Output.Show(jaaa.ToString)
[此贴子已经被作者于2020/7/20 17:13:28编辑过]
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-- 作者:李孝春 -- 发布时间:2020/7/20 17:35:00 -- 回复:(有点蓝)Dim Arys As List(Of String())Arys ... 再麻烦老师指导下 上述代码运行还是没有成功 提示如下: jo("date").add(jo2) 这个提示没有ADD成员 我tab查看 精灵提示里面只有parse tostring两个
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-- 作者:有点蓝 -- 发布时间:2020/7/21 8:20:00 -- For Each Ary As String() In Arys Output.Show(Ary(0) & "|" & Ary(1)) jo = New JObject jo("danweiname") = Ary(0) jo("name") = Ary(1) dim ja2 as New JArray\' For Each dr As DataRow In DataTables("josn").Select("danweiname= \'" & Ary(0) & "\' and name=\'" & Ary(1) & "\'") Output.Show(dr("tiem")) Output.Show(dr("context")) jo2 = New JObject jo2("tiem") = dr("tiem") jo2("context") = dr("context") ja2.add(jo2) Next jo("date") = ja2 jaaa.Add(jo) Next
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-- 作者:李孝春 -- 发布时间:2020/7/21 9:14:00 -- 老师 还是有点小问题 没有能够成功生成想要的josn 麻烦老师指导下 代码内容 Dim Arys As List(Of String()) Arys = DataTables("josn").GetValues("danweiname|name") Dim jaaa As New JArray Dim jo,jo2 As JObject For Each Ary As String() In Arys Output.Show(Ary(0) & "|" & Ary(1)) jo = New JObject jo("danweiname") = Ary(0) jo("name") = Ary(1) Dim ja2 As New JArray\' For Each dr As DataRow In DataTables("josn").Select("danweiname= \'" & Ary(0) & "\' and name=\'" & Ary(1) & "\'") Output.Show(dr("tiem")) Output.Show(dr("context")) jo2 = New JObject jo2("tiem") = dr("tiem") jo2("context") = dr("context") ja2.add(jo2) Next jo("date") = ja2 jaaa.Add(jo) Next 运行提示: [此贴子已经被作者于2020/7/21 9:17:15编辑过]
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-- 作者:有点蓝 -- 发布时间:2020/7/21 9:41:00 -- jo2("tiem") = cstr(dr("tiem")) |
-- 作者:李孝春 -- 发布时间:2020/7/21 17:47:00 -- 回复:(有点蓝)jo2("tiem") = cstr(dr("tiem")) 有点蓝老师 经过你的指导 现在代码如下: Dim Arys As List(Of String()) Arys = DataTables("josn").GetValues("danweiname|name") Dim jaaa As New JArray Dim jo,jo2 As JObject For Each Ary As String() In Arys \'Output.Show(Ary(0) & "|" & Ary(1)) jo = New JObject jo("danweiname") = Ary(0) jo("name") = Ary(1) Dim ja2 As New JArray\' For Each dr As DataRow In DataTables("josn").Select("danweiname= \'" & Ary(0) & "\' and name=\'" & Ary(1) & "\'") \'Output.Show(dr("tiem")) \'Output.Show(dr("context")) jo2 = New JObject jo2("tiem") = cstr(dr("tiem")) jo2("context") = cstr(dr("context")) ja2.add(jo2) Next jo("date") = ja2 jaaa.Add(jo) Next \'Output.Show(jaaa.ToString) Dim content As String content &= jaaa.ToString \'Output.Show(content) Dim lj As String = Date.Today & "save.json" Dim FileName As String = ProjectPath & lj FileSys.WriteAllText(FileName, content, True) 代码运行后得到的json达到预期,并且成功将json内容写入文件里 [ { "danweiname": "AAAA", "name": "BB", "date": [ { "tiem": "2020-09-01", "context": "CES" }, { "tiem": "2020-11-11", "context": "REW" }, { "tiem": "2020-12-12", "context": "TRE" } ] }, { "danweiname": "AAAA", "name": "QQ", "date": [ { "tiem": "2019-12-12", "context": "UY" }, { "tiem": "2020-11-21", "context": "IUYIU" } ] }, { "danweiname": "BBBB", "name": "CC", "date": [ { "tiem": "2019-03-20", "context": "RTYE" }, { "tiem": "2020-09-03", "context": "EWR" } ] }, { "danweiname": "CCCC", "name": "WW", "date": [ { "tiem": "2018-09-01", "context": "TREWR" }, { "tiem": "2019-02-01", "context": "Q" } ] }, { "danweiname": "DDDD", "name": "EE", "date": [ { "tiem": "2020-07-21", "context": "432W" } ] } ] 参照帮助代码如下: Dim json As String = jaaa.ToString Dim jojo As JObject = JObject.Parse(json) Output.Show("单位名称:" & jojo("danweiname")) Output.Show("姓名:" & jojo("name")) For Each ep As JToken In jojo("date") Output.Show( "日期:" & ep("tiem").ToString() & "记录:" & ep("cotext").ToString() ) Next 运行无法正常,提示报错,麻烦看看是不是我将json结构理解有误。 [此贴子已经被作者于2020/7/21 17:48:00编辑过]
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-- 作者:李孝春 -- 发布时间:2020/7/21 18:00:00 -- 回复:(有点蓝)jo2("tiem") = cstr(dr("tiem")) 有点蓝老师 参照你发布在论坛里的exweui我试一下将所生成的json文件解析成如下页面 没有成功 麻烦老师指导下 谢谢 以下内容是专门发给李孝春浏览 内部函数名json 内容: Dim e As RequestEventArgs = args(0) Dim wb As New weui wb.AppendHTML("<link rel=\'stylesheet\' href=\'./weui/exweui.css\'/>",True) Dim fl As String = HttpServer.WebPath & "\\save.json" If FileSys.FileExists(fl) Dim txt As String = FileSys.ReadAllText(fl) Dim jo As JObject = Jobject.Parse(txt) \'If jo("danweiname") IsNot Nothing Then With ExWeUI.WebUI.AddStepGroup("","step1","",,2) For Each jt As JToken In jo("date") With .AddStep("st01","",jt("tiem").ToString) .Description = jt("context").ToString End With Next wb.InsertHTML(.BuildHtml) End With \'End If e.WriteString(wb.Build) Else e.WriteString("没有查到信息") End If 运行后页面提示错误 .NET Framework 版本:4.0.30319.42000 Foxtable 版本:2020.5.29.8 错误所在事件:自定义函数,json 详细错误信息: 调用的目标发生了异常。 Error reading JObject from JsonReader. Current JsonReader item is not an object: StartArray. Path \'\', line 1, position 1. |