以文本方式查看主题 - Foxtable(狐表) (http://foxtable.com/bbs/index.asp) -- 专家坐堂 (http://foxtable.com/bbs/list.asp?boardid=2) ---- 移动开发端 如何实现判断AddInput不为空时,允许点击登录呢? (http://foxtable.com/bbs/dispbbs.asp?boardid=2&id=133146) |
-- 作者:李孝春 -- 发布时间:2019/4/8 11:30:00 -- 移动开发端 如何实现判断AddInput不为空时,允许点击登录呢? 移动开发端 如何实现判断AddInput不为空时,允许点击登录呢? 代码如下: Select Case e.Path Case "logon.htm" \'登录页面 wb.AddPageTitle("","pageheader","案件流程推送","由瓮安县人民检察院李孝春设计开发") If e.PostValues.ContainsKey("username") AndAlso e.PostValues.ContainsKey("password") Then \'判断是否是验证失败后的重新登录 wb.AddTopTips("","toptip1","用户名或密码错误!").msec = 2000 \'如果用户通过登录按钮访问,则给用户一个2秒的提示. End If wb.AddForm("","form1","logon.htm") With wb.AddInputGroup("form1","ipg1") .AddInput("username","户名","text") .AddInput("password","密码","password") End With With wb.AddButtonGroup("form1","btg1",True) .Add("btn1", "登录", "submit") End With With wb.AddPageFooter("","pf1","Copyright © 贵州省瓮安县人民检察院") \'.AddLink("底部链接","http://www.foxtable.com") End With e.WriteString(wb.Build)
|
-- 作者:有点甜 -- 发布时间:2019/4/8 12:25:00 -- 用js做一下校验吧,如
Select Case e.Path |