以文本方式查看主题 - Foxtable(狐表) (http://foxtable.com/bbs/index.asp) -- 专家坐堂 (http://foxtable.com/bbs/list.asp?boardid=2) ---- [求助]文本框内容转目录树 (http://foxtable.com/bbs/dispbbs.asp?boardid=2&id=119543) |
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-- 作者:天一生水 -- 发布时间:2018/5/26 18:08:00 -- [求助]文本框内容转目录树 如图,文本框中的每一行文本,都是由“时间”、“文书”、“接收人”、“诉讼地位”四部分组成的,中间用逗号分隔;然后换行。 怎样将这多行文本转为目录树,比如目录树的节点层级就按照上述四部分的顺序。 谢谢! |
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-- 作者:有点甜 -- 发布时间:2018/5/27 16:09:00 --
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-- 作者:天一生水 -- 发布时间:2019/4/22 12:18:00 -- 老师好! 获取的4组数据,如果我只想生成3层目录树。根节点命名为是s(0),第2层命名为是s(1),第3层命名为是s(2)& "(" & s(3) & ")" 。 如图所示,应该怎样修改? 谢谢!
DataFormat事件: \'\'\' |
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-- 作者:有点甜 -- 发布时间:2019/4/22 12:43:00 -- \'\'\' Dim ary() As String = e.Text.split(";") Dim trv As WinForm.TreeView = e.Form.controls("Treeview1") If trv Is Nothing Then Return trv.nodes.clear For Each str As String In ary Dim s() As String = str.split(",") If s.length <> 4 Then Continue For Dim n1 As WinForm.TreeNode = Nothing Dim n2 As WinForm.TreeNode = Nothing Dim n3 As WinForm.TreeNode = Nothing Dim n4 As WinForm.TreeNode = Nothing For Each nd1 As WinForm.TreeNode In trv.Nodes If nd1.name = s(0).trim Then n1 = nd1 For Each nd2 As WinForm.TreeNode In nd1.Nodes If nd2.name = s(1).trim Then n2 = nd2 For Each nd3 As WinForm.TreeNode In nd2.Nodes If nd3.name = s(2).trim Then n3 = nd3 End If Next End If Next End If Next If n1 Is Nothing Then n1 = trv.nodes.Add(s(0).trim) End If If n2 Is Nothing Then n2 = n1.nodes.Add(s(1).trim) End If If n3 Is Nothing Then n3 = n2.nodes.Add(s(2).trim, s(2).trim & "(" & s(3) & ")") End If Next |