将“数据表”的[被告出庭]内容，按照被告的不同在“机关负责人出庭”进行拆分，见下图：

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谢谢！

谢谢老师！

我改了一句代码，需要同时找[案号]和[被告]，然后拆分。是哪里错了？

\'\'\'
If e.DataCol.name = "被告出庭" Then
    Dim str As String = e.NewValue
    If str > "" Then
        Dim ary() As String = str.Replace("被告", "@").split("@")
       
        For i As Integer = 0 To ary.length-1
            str = ary(i).trim()
            If str > "" Then
                str = "被告" & str
                Dim mc = System.Text.RegularExpressions.Regex.Matches(str, "(?<=被告).*?(?=。)")   \'提取被告单位名称
                Dim s As String = mc(0).value
                Dim dr = DataTables("机关负责人出庭").Find("[案号] = \'" & e.DataRow("案号") & "\'"  AndAlso "[被告] = \'" & s.split("，")(0) & "\'")      \'到信息表去找
                If dr Is Nothing Then
                    dr = DataTables("机关负责人出庭").AddNew
                End If
                dr("案号") = e.DataRow("案号")
                dr("被告") = s.split("，")(0)
                dr("被告出庭拆分") = str
               
            End If
        Next
    End If
End If